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Relative Entropy and Linearized Gravity

The RT and HRT formulas say that boundary entanglement knows about bulk geometry. Relative entropy says something sharper: the consistency conditions of boundary quantum information know about the bulk equations of motion.

The basic chain is

relative entropyδSA=δKAgravitational first lawδEab=0.\text{relative entropy} \quad\Longrightarrow\quad \delta S_A=\delta\langle K_A\rangle \quad\Longrightarrow\quad \text{gravitational first law} \quad\Longrightarrow\quad \delta E_{ab}=0.

Here KAK_A is the modular Hamiltonian of a boundary region AA, and δEab=0\delta E_{ab}=0 denotes the bulk gravitational equations linearized around AdS. The result is not a slogan about “gravity equals entanglement.” It is a precise statement, in a controlled regime, that the CFT entanglement first law for all ball-shaped regions is equivalent to the linearized Einstein equations in the bulk.

A boundary ball, its RT surface, and the logic by which the entanglement first law becomes the linearized Einstein equation.

For a vacuum CFT ball BB, modular flow is generated by a conformal Killing vector. In pure AdS this lifts to an AdS-Rindler Killing vector ξB\xi_B that vanishes on the RT surface B~\widetilde B. The difference δKBδSB\delta\langle K_B\rangle-\delta S_B is a bulk integral of the linearized gravitational equations over ΣB\Sigma_B.

The previous pages introduced entanglement wedges: the bulk regions associated with boundary reduced density matrices. This page goes one step deeper. It explains why the RT/HRT area formula is tied not only to bulk geometry, but also to bulk dynamics.

A gravitational theory is not specified by geometry alone. It also needs equations of motion. In AdS/CFT, those equations are not extra data appended to the boundary theory. They are encoded in consistency conditions of CFT observables. Relative entropy is one of the cleanest observables for seeing this because it is exact, positive, monotonic, and defined purely in quantum-mechanical terms.

The central lesson is

entanglement first law for all CFT ballslinearized bulk gravity around AdS.\boxed{ \text{entanglement first law for all CFT balls} \quad\Longleftrightarrow\quad \text{linearized bulk gravity around AdS}. }

The assumptions are important. We work near the vacuum of a holographic CFT, use ball-shaped boundary regions, and keep the leading classical RT contribution to entropy. Quantum corrections lead to generalized entropy and quantum extremal surfaces, which are introduced on the next page.

Let ρA\rho_A and σA\sigma_A be two density matrices on the same region AA. Their relative entropy is

S(ρAσA)=Tr(ρAlogρA)Tr(ρAlogσA).S(\rho_A\|\sigma_A) = \operatorname{Tr}(\rho_A\log\rho_A) - \operatorname{Tr}(\rho_A\log\sigma_A).

Define the modular Hamiltonian of the reference state σA\sigma_A by

KA(σ)=logσA.K_A^{(\sigma)}=-\log\sigma_A.

The relative entropy can then be written as

S(ρAσA)=ΔKA(σ)ΔSA,S(\rho_A\|\sigma_A) = \Delta\langle K_A^{(\sigma)}\rangle- \Delta S_A,

where

ΔKA(σ)=Tr(ρAKA(σ))Tr(σAKA(σ)),\Delta\langle K_A^{(\sigma)}\rangle = \operatorname{Tr}(\rho_AK_A^{(\sigma)}) - \operatorname{Tr}(\sigma_AK_A^{(\sigma)}),

and

ΔSA=S(ρA)S(σA).\Delta S_A=S(\rho_A)-S(\sigma_A).

Relative entropy has two essential properties:

S(ρAσA)0,S(\rho_A\|\sigma_A)\ge0,

and, if ABA\subseteq B,

S(ρAσA)S(ρBσB).S(\rho_A\|\sigma_A) \le S(\rho_B\|\sigma_B).

The second property is monotonicity under restriction: a larger region contains at least as much information for distinguishing two states as a smaller region.

Consider a one-parameter family of states

ρA(λ)=σA+λδρA+O(λ2),TrδρA=0.\rho_A(\lambda)=\sigma_A+\lambda\delta\rho_A+O(\lambda^2), \qquad \operatorname{Tr}\delta\rho_A=0.

Since S(ρAσA)S(\rho_A\|\sigma_A) has a minimum at ρA=σA\rho_A=\sigma_A, its first variation vanishes:

δS(ρAσA)=0.\delta S(\rho_A\|\sigma_A)=0.

Using

S(ρAσA)=ΔKA(σ)ΔSA,S(\rho_A\|\sigma_A) = \Delta\langle K_A^{(\sigma)}\rangle- \Delta S_A,

we obtain the entanglement first law:

δSA=δKA(σ).\boxed{ \delta S_A=\delta\langle K_A^{(\sigma)}\rangle. }

This is a kinematic identity in quantum mechanics. It does not require holography. Holography enters when we translate both sides into bulk quantities.

For a general region AA, the modular Hamiltonian is highly nonlocal. For a ball-shaped region in the vacuum of a CFT, it is local.

Let BB be a ball of radius RR centered at x0\vec x_0 on the boundary time slice t=t0t=t_0:

B={x:xx0<R}.B=\{\vec x: |\vec x-\vec x_0|<R\}.

For the CFT vacuum on flat space,

KB=2πBdd1xR2xx022RT00(t0,x)+constant.K_B = 2\pi \int_B d^{d-1}x\, \frac{R^2-|\vec x-\vec x_0|^2}{2R} T_{00}(t_0,\vec x) + \text{constant}.

The additive constant normalizes ρB\rho_B and drops out of variations. Therefore

δKB=2πBdd1xR2xx022RδT00(t0,x).\delta\langle K_B\rangle = 2\pi \int_B d^{d-1}x\, \frac{R^2-|\vec x-\vec x_0|^2}{2R} \delta\langle T_{00}(t_0,\vec x)\rangle.

This formula makes the modular-energy variation a weighted integral of the stress-tensor one-point function.

On the bulk side, in Poincaré AdS,

ds2=L2z2(dt2+dz2+dx2),ds^2=\frac{L^2}{z^2} \left(-dt^2+dz^2+d\vec x^{\,2}\right),

the RT surface for the vacuum ball is the hemisphere

z2+xx02=R2,t=t0.z^2+|\vec x-\vec x_0|^2=R^2, \qquad t=t_0.

This ball/hemisphere pair is the cleanest laboratory for seeing dynamics from entanglement.

The causal development D[B]D[B] of the boundary ball is generated by a conformal Killing vector. In pure AdS, this lifts to an exact bulk Killing vector. For a ball centered at t=0t=0, x=0\vec x=0, one convenient expression is

ξB=πR[(R2z2x2t2)t2t(zz+xii)].\xi_B = \frac{\pi}{R} \left[ \left(R^2-z^2-\vec x^{\,2}-t^2\right)\partial_t -2t\left(z\partial_z+x^i\partial_i\right) \right].

This vector has three important features.

First, near the boundary it becomes the conformal Killing vector that generates modular flow in D[B]D[B].

Second, on the RT surface

t=0,z2+x2=R2,t=0, \qquad z^2+\vec x^{\,2}=R^2,

it vanishes:

ξB=0.\xi_B=0.

Third, it generates an AdS-Rindler horizon for the entanglement wedge of the ball. This is why the entanglement first law has the same mathematical structure as a gravitational first law.

Now perturb the CFT vacuum. In the bulk, this corresponds to a small metric perturbation

gab=gabAdS+hab.g_{ab}=g_{ab}^{\mathrm{AdS}}+h_{ab}.

The boundary stress tensor expectation value is read from the near-boundary behavior of habh_{ab}. Thus δKB\delta\langle K_B\rangle becomes a gravitational charge associated with ξB\xi_B.

The entropy variation is computed using RT:

δSB=δ(Area(B~)4GN).\delta S_B = \delta\left(\frac{\operatorname{Area}(\widetilde B)}{4G_N}\right).

Because B~\widetilde B is extremal in the unperturbed geometry, the first-order change in area can be computed by varying the metric on the original surface. The first-order shift of the surface does not contribute.

The remarkable identity is that

δKBδSB=ΣBξBaδEabϵb.\delta\langle K_B\rangle- \delta S_B = \int_{\Sigma_B} \xi_B^a\,\delta E_{ab}\,\epsilon^b.

Here ΣB\Sigma_B is the bulk region bounded by BB and B~\widetilde B, ϵb\epsilon^b is the natural volume-form vector on ΣB\Sigma_B, and δEab\delta E_{ab} denotes the linearized equations of motion. For Einstein gravity with cosmological constant and no bulk matter perturbation,

δEab=δ(Rab12Rgab+Λgab).\delta E_{ab} = \delta\left(R_{ab}-\frac12 Rg_{ab}+\Lambda g_{ab}\right).

With matter, the equation is instead schematically

δEab=8πGNδTabbulk.\delta E_{ab}=8\pi G_N\,\delta T_{ab}^{\mathrm{bulk}}.

This identity is a version of the Iyer–Wald relation: the difference between a boundary charge variation and a horizon-area variation is controlled by the equations of motion in the region between them.

From integral constraints to local equations

Section titled “From integral constraints to local equations”

The CFT entanglement first law says

δKBδSB=0.\delta\langle K_B\rangle- \delta S_B=0.

Therefore

ΣBξBaδEabϵb=0\int_{\Sigma_B} \xi_B^a\,\delta E_{ab}\,\epsilon^b=0

for every ball BB.

A single such integral would not imply a local equation. But the family of all balls, with arbitrary centers, radii, and times, is powerful enough to probe the perturbation throughout the bulk. Under appropriate regularity and boundary assumptions, these integral constraints imply

δEab=0.\boxed{ \delta E_{ab}=0. }

For Einstein gravity, this is the linearized Einstein equation around AdS:

δ(Rab12Rgab+Λgab)=0.\boxed{ \delta\left(R_{ab}-\frac12 Rg_{ab}+\Lambda g_{ab}\right)=0. }

Thus, for a holographic CFT whose leading entropy is computed by RT, the entanglement first law for all vacuum balls is equivalent to linearized classical gravity in the bulk.

The first law comes from the first variation of relative entropy. The second variation is nonzero and positive:

S(ρAσA)=O(δρ2)0.S(\rho_A\|\sigma_A)=O(\delta\rho^2)\ge0.

In holography, this second-order quantity is related to canonical energy in the bulk. Schematically, for perturbations around the vacuum,

S(ρBρBvac)=Ecanbulk[h,h]+O(h3).S(\rho_B\|\rho_B^{\mathrm{vac}}) = E_{\mathrm{can}}^{\mathrm{bulk}}[h,h]+O(h^3).

This is more than a curiosity. Positivity and monotonicity of boundary relative entropy impose positivity constraints on the bulk theory. In this way, ordinary quantum-information inequalities become consistency conditions for gravitational effective field theory.

The modern form of the story is the JLMS relation. For a boundary region AA with entanglement wedge aa, the boundary modular Hamiltonian has the schematic code-subspace form

KACFT=Area^(XA)4GN+Kabulk+.K_A^{\mathrm{CFT}} = \frac{\widehat{\operatorname{Area}}(X_A)}{4G_N} +K_a^{\mathrm{bulk}} +\cdots.

Here XAX_A is the HRT surface, KabulkK_a^{\mathrm{bulk}} is the modular Hamiltonian of bulk quantum fields in the entanglement wedge, and the ellipsis hides subtleties involving gauge constraints, edge modes, operator ordering, and higher-order corrections.

The relative-entropy statement is even cleaner:

S(ρAσA)=Sbulk(ρaσa)+controlled gravitational terms.S(\rho_A\|\sigma_A) = S_{\mathrm{bulk}}(\rho_a\|\sigma_a) + \text{controlled gravitational terms}.

In the appropriate semiclassical code subspace, boundary relative entropy is matched by relative entropy in the entanglement wedge. This is one of the strongest pieces of evidence for entanglement wedge reconstruction.

The clean derivation of linearized Einstein equations assumes:

  1. a CFT state close to the vacuum;
  2. ball-shaped boundary regions;
  3. a bulk geometry close to pure AdS;
  4. the classical RT formula at leading order;
  5. the standard holographic stress-tensor dictionary;
  6. suitable regularity and boundary conditions.

It does not by itself prove full nonlinear quantum gravity. Extensions use higher-order relative entropy, canonical energy, bulk quantum corrections, and modular-flow technology. The foundational result is already deep: local bulk dynamics can be read from boundary entanglement consistency.

Boundary statementBulk statement
modular Hamiltonian KBK_B of a vacuum ballAdS-Rindler charge generated by ξB\xi_B
entanglement first law δSB=δKB\delta S_B=\delta\langle K_B\ranglegravitational first law for B~\widetilde B
relative entropy positivitypositivity of bulk canonical energy
first law for all ballslinearized Einstein equations around AdS
boundary modular Hamiltonian in a code subspacearea operator plus bulk modular Hamiltonian
boundary relative entropybulk relative entropy in the entanglement wedge

The new moral is

geometry is not enough; entanglement also knows the equations of motion.\boxed{ \text{geometry is not enough; entanglement also knows the equations of motion.} }

“The entanglement first law is dynamical.”

Section titled ““The entanglement first law is dynamical.””

The first law is kinematic. It follows from the definition of relative entropy. The dynamics appears only after the holographic translation of both sides.

“One ball is enough to derive Einstein’s equations.”

Section titled ““One ball is enough to derive Einstein’s equations.””

No. One ball gives one integral constraint. The local equations follow from imposing the first law for all balls.

No. The basic argument gives linearized equations around AdS. Nonlinear and quantum extensions require additional input.

“Relative entropy is just entanglement entropy.”

Section titled ““Relative entropy is just entanglement entropy.””

No. Entanglement entropy is a property of one state. Relative entropy compares two states and combines modular energy with entropy:

S(ρσ)=ΔKσΔS.S(\rho\|\sigma)=\Delta\langle K_\sigma\rangle-\Delta S.

Exercise 1: Derive the entanglement first law

Section titled “Exercise 1: Derive the entanglement first law”

Let ρ(λ)=σ+λδρ+O(λ2)\rho(\lambda)=\sigma+\lambda\delta\rho+O(\lambda^2) with Trδρ=0\operatorname{Tr}\delta\rho=0. Use

S(ρσ)=ΔKσΔSS(\rho\|\sigma)=\Delta\langle K_\sigma\rangle-\Delta S

to show that δS=δKσ\delta S=\delta\langle K_\sigma\rangle.

Solution

Relative entropy is nonnegative and has a minimum at ρ=σ\rho=\sigma:

S(σσ)=0.S(\sigma\|\sigma)=0.

Therefore its first variation around σ\sigma vanishes:

δS(ρσ)=0.\delta S(\rho\|\sigma)=0.

Using

S(ρσ)=ΔKσΔS,S(\rho\|\sigma)=\Delta\langle K_\sigma\rangle-\Delta S,

we get

0=δKσδS,0=\delta\langle K_\sigma\rangle-\delta S,

so

δS=δKσ.\delta S=\delta\langle K_\sigma\rangle.

Exercise 2: Deepest point of the ball RT surface

Section titled “Exercise 2: Deepest point of the ball RT surface”

For the hemisphere

z2+r2=R2,z^2+r^2=R^2,

find the deepest radial point.

Solution

The deepest point has r=0r=0, so

z2=R2.z^2=R^2.

Thus

z=R.z_\ast=R.

A larger boundary ball probes deeper into the bulk.

Exercise 3: Why the surface shift does not contribute at first order

Section titled “Exercise 3: Why the surface shift does not contribute at first order”

Explain why the first-order variation of the RT entropy can be computed on the unperturbed extremal surface.

Solution

Let the area functional be A[X,g]A[X,g]. Its first variation is

δA=δAδgX0δg+δAδXX0δX.\delta A = \left.\frac{\delta A}{\delta g}\right|_{X_0}\delta g + \left.\frac{\delta A}{\delta X}\right|_{X_0}\delta X.

Since X0X_0 is extremal in the background geometry,

δAδXX0=0.\left.\frac{\delta A}{\delta X}\right|_{X_0}=0.

Therefore the first-order area change comes only from the metric perturbation evaluated on the original surface.

Why does

ΣBξBaδEabϵb=0\int_{\Sigma_B}\xi_B^a\delta E_{ab}\epsilon^b=0

for a single ball not imply δEab=0\delta E_{ab}=0 pointwise?

Solution

A single integral constraint only fixes one weighted average of δEab\delta E_{ab}. A nonzero function can have a vanishing weighted integral over one region. The local equation follows only after imposing such constraints for a sufficiently rich family of regions and weights, here all boundary balls.